I am 99% sure this is not correct, so What did I do wrong?
4x + 2y = 12
-6x + 3y = 6
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5y 12
---- ----
5 5
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Y = 3.6.... (Thats how far I went)
3x - 2y = 0
3x - 2y = -4
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4y -4
---- ----
4 4
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x = -1 (I went that far only)
2x + y <(With the line at the bottom) 1
-2x + y <(With the line at the bottom) 1
(How do I do that?)
Same with this one
2x + Y >(Line at bottom) 2
X < (Line at bottom) 2
X + 2y < 3
X - -3y > 1
Im WTF right now....
(1/10) to the -3rd power... -6x + 3y = 6
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1st you have to get 2 of the #s equal but opposite. like 2 and -2.
6(4x+2y=12) = 24x+12y=72
4(-6x+3y=6) = -24x+12y=24
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now you can get rid of 1 set of variables so u can simplify it easier. get rid of the 24x and -24x by adding the equations together.
24x-24x=0, 12y+12y=24y, and 72+24=96, so now the new equation is:
24y=96.
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now divide both sides so thhat the # with the y is 1 (1y). divide both sides of the equation by 24.
24y divided by 24 = y 96 divided by 24 = 8
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so........... Y = 8.
for the next one you can do the exact same thing.
2x+y <(or equal to) 1
-2x+y<(or equal to) 1
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you have to do basicly the same thing, combining like terms, or the #s with the same letters attached to them, so you only have one variable( instead of x and y, you have only a y, or viceversa)
2x+ -2x = 0
Y+Y= 2Y
1+1=2
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now you have 2Y=2. divide so that you only have one y.
2y divided by 2=y, 2 divided by 2 =1
so y=1.
do that for the others like it also.
FOR ALL PROBLEMS:
if you have already solved for one variable, then you plug thet # into the variable's place and solve the same way. for example, X+Y=19
-X+Y=13
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2y=32
Y=16
then you plug it in to one of the equations.
X+(16)=19
again, you get rid of the #s so u have one variable, and only that, on one side.
16-16=0, 19-16=3
X=3
sorry if its really long and hard to understand but i tried, and i know for sure that i am right. good luck with the others.
GO WARRIORS!!!!!!!