How to do this physics problem? A car (m = 1730 kg) is parked on a road that rises 13.1 ° above the horizontal. What are the magnitudes of (a) the normal force and (b) the static frictional force that the ground exerts on the tires?

Because the car is parked and not moving the net force on the car must be 0N

Weight = m*g
A car with a mass of 1730 kg has a weight of 1730 kg *9.8 m/s^2 = 16.95 x 10^3 N

This weight can be broken down into forces parallel to the surface and perpendicular to the surface
Fparallel = W * sin 13.1 = 3.84x10^3N
This means that the friciton force must also be 3.84x10^3 N otherwise the car would accelerate down the hill

Fperp = W * cos 13.1 = 16.51x10^3 N
This means that the normal force must also be 16.51x10^3 N otherwise the car would accelerate through the surface of the road.